Name
a64l, l64a — convert between long and base-64
Synopsis
#include <stdlib.h>
long
a64l( |
char * | str64); |
char
*l64a( |
long | value); |
![[Note]](../stylesheet/note.png) |
Note | ||
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DESCRIPTION
These functions provide a conversion between 32-bit long
integers and little-endian base-64 ASCII strings (of length
zero to six). If the string used as argument for a64l() has length greater than six, only
the first six bytes are used. If the type long has more than 32 bits, then l64a() uses only the low order 32 bits of
value, and
a64l() sign-extends its 32-bit
result.
The 64 digits in the base-64 system are:
'.' represents a 0 '/' represents a 1 0-9 represent 2-11 A-Z represent 12-37 a-z represent 38-63
So 123 = 59*64^0 + 1*64^1 = "v/".
NOTES
The value returned by a64l()
may be a pointer to a static buffer, possibly overwritten by
later calls.
The behavior of l64a() is
undefined when value
is negative. If value
is zero, it returns an empty string.
These functions are broken in glibc before 2.2.5 (puts most significant digit first).
This is not the encoding used by uuencode(1).
COLOPHON
This page is part of release 2.79 of the Linux man-pages project. A
description of the project, and information about reporting
bugs, can be found at
http://www.kernel.org/doc/man-pages/.
|
Copyright 2002 walter harms (walter.harmsinformatik.uni-oldenburg.de) Distributed under GPL Corrected, aeb, 2002-05-30 |