stpcpy — copy a string returning a pointer to its
end
Synopsis
#define _GNU_SOURCE
#include <string.h>
char
*stpcpy(
char *
dest,
const char *
src);
DESCRIPTION
The stpcpy() function copies
the string pointed to by src (including the terminating
'\0' character) to the array pointed to by dest. The strings may not
overlap, and the destination string dest must be large enough to
receive the copy.
RETURN VALUE
stpcpy() returns a pointer
to the end of the
string dest (that is,
the address of the terminating null byte) rather than the
beginning.
CONFORMING TO
This function is not part of the C or POSIX.1 standards,
and is not customary on Unix systems, but is not a GNU
invention either. Perhaps it comes from MS-DOS.
EXAMPLE
For example, this program uses stpcpy() to concatenate “foo” and “bar” to produce “foobar”, which it then prints.
#include <string.h>
int
main (void)
{
char *to = buffer;
to = stpcpy(to, "foo");
to = stpcpy(to, "bar");
printf("%s\n", buffer);
}
This page is part of release 2.79 of the Linux man-pages project. A
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Copyright 1995 James R. Van Zandt <jrv@vanzandt.mv.com>
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